Question
Solve the following system of equations in R. $\frac{|\text{x}+2|-\text{x}}{\text{x}}<2$

Answer

We have, $\frac{|\text{x}+2|-\text{x}}{\text{x}}<0$ $\frac{|\text{x}+2|-\text{x}}{\text{x}}-2<0$ $\frac{|\text{x}+2|-\text{x}-2\text{x}}{\text{x}}<0$ $\frac{|\text{x}+2|-3\text{x}}{\text{x}}<0\ ...(\text{i})$ Case 1: When $|\text{x}+2|\geq0$ $\Rightarrow\frac{\text{x}+2-3\text{x}}{\text{x}}<0$ ⇒ - 2x + 2 < 0 ⇒ -2x < - 2 and x > 0 ⇒ x > 1 ...(ii) case2: |x + 2|< 0 x < -2 ⇒ -(x + 2)- 3x < 0 ⇒ - x - 2 - 3x < 0 ⇒ -4x - 2 < 0 ⇒ -4x < 2 $\Rightarrow\text{x}>\frac{-1}{2}\ ...(\text{iii})$ and x < 0 Combining (ii) and (iii), we get $(-\infty,0)\cup(1,\infty)$ as the solution set.

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