Question
Solve the following systems of equations:
${\text{x}}+\frac{\text{y}}{2}=4,$
$\frac{\text{x}}{3}+2\text{y}=5.$
${\text{x}}+\frac{\text{y}}{2}=4,$
$\frac{\text{x}}{3}+2\text{y}=5.$
✓
Answer
The given equations are, ${\text{x}}+\frac{\text{y}}{2}=4\ .....(\text{i})$ $\frac{\text{x}}{3}+2\text{y}=5\ ......(\text{ii})$ Multiply equation (i) by 4 and subtract equations (i) - (ii), we get 4x + 2y = 16
$\Rightarrow\text{x}=3$ Put the value of x in equation (i), we get $3+\frac{\text{y}}{2}=4$ $\Rightarrow\frac{\text{y}}{2}=1$ $\Rightarrow\text{y}=2$ Hence the value of x and y are x = 3 and y = 2.
$\Rightarrow\text{x}=3$ Put the value of x in equation (i), we get $3+\frac{\text{y}}{2}=4$ $\Rightarrow\frac{\text{y}}{2}=1$ $\Rightarrow\text{y}=2$ Hence the value of x and y are x = 3 and y = 2.
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