Question
Solve the inequality and represent the solution graphically on number line: 5x + 1 > – 24, 5x – 1 < 24
✓
Answer
Given inequalities 5x + 1 > -24 and 5x – 1 < 24
5x + 1 > -24
$\Rightarrow$ 5x > -24 – 1
$\Rightarrow$ 5x > -25
$\Rightarrow$ x > -5 ………(I)
5x – 1 < 24
$\Rightarrow$ 5x < 24 + 1
$\Rightarrow$ 5x < 25
$\Rightarrow$ x < 5 ……….(II)
From (I) and (II) we conclude that the solution of given inequalities is (-5, 5).
5x + 1 > -24
$\Rightarrow$ 5x > -24 – 1
$\Rightarrow$ 5x > -25
$\Rightarrow$ x > -5 ………(I)
5x – 1 < 24
$\Rightarrow$ 5x < 24 + 1
$\Rightarrow$ 5x < 25
$\Rightarrow$ x < 5 ……….(II)
From (I) and (II) we conclude that the solution of given inequalities is (-5, 5).
solution set (-5,5)
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Prove that: $\sin^2\text{(n+1)}\text{A}-\sin^2\text{nA}=\sin\text{(2n+1)}\text{A}\sin\text{A}$
→Find the rate at which the function $\text{f}(\text{x})=\text{x}^4-\text{2x}^3+\text{3x}^2+\text{x}+5$change with respect to $\text{x}.$
→Differentiate the following function with respect to x:$\text{x}^{-4}(3-\text{4x}^{-5})$
→Find the sum of the product of the corresponding terms of the sequences $2,4,8,16,32$ and $128,32,8,2, \frac{1}{2}$.
→A(1, 2, 3), B(0, 4, 1), C(-1, -1, -3) are the vertices of a triangle ABC. Find the point in which the bisector of the angle $\angle\text{BAC}$ meets BC.
→For any two sets A and B, show that the following statements are equevalent:
$\text{A}\cap\text{B}=\text{A}.$
→$\text{A}\cap\text{B}=\text{A}.$
Find the coordinates of the foci, the vertices, the length of major axis, the minor axis, the eccentricity and the length of the latus rectum of the ellipse.
$\frac{{{x^2}}}{{16}} + \frac{{{y^2}}}{9} = 1$
→$\frac{{{x^2}}}{{16}} + \frac{{{y^2}}}{9} = 1$
The difference between any two consecutive interior angles of a polygon is $5^{\circ}$. If the smallest angle is $120^{\circ}$. find the number of the sides of the polygon.
→Find an A.P. in which the sum of any number of terms is always three times the squared number of these terms.
Evaluate the following limit: $\lim\limits_{\text{x}\rightarrow0}\frac{\sqrt{1+\text{x}+\text{x}^2}-1}{\text{x}}$
→