$-1<3-\frac{x}{5} \leq 1$ Subtracting 3 from both sides, we get $-4<-\frac{x}{5}<-2$ Multiplying by -1 throughout (so inequality sign changes) $\therefore 4>\frac{x}{5}>2$ i.e., $2<\frac{x}{5}<4$ Multiplying by 5 on both sides, we get $ 10<x<20 $ i.e., $x$ takes all real values between 10 and 20 . $\therefore$ the solution set is $(10,20)$
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