Question
Solve the inequations: $4-2 x<3(3-x)$

Answer

$
\begin{aligned}
& 4-2 x<3(3-x) \\
& \therefore 4-2 x<9-3 x
\end{aligned}
$
Adding $3 x$ on both sides, we get
$
4+x<9
$
Subtracting 4 from both sides, we get
$
x<5
$
i.e., $\mathrm{x}$ takes all real values less than 5
$\therefore$ the solution set is $(-\infty, 5)$

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