Question
Solve the quadratic equation $x^2+2 \sqrt{2 x}-6=0$ for $x$.

Answer

Given quadratic equation is:
$x^2+2 \sqrt{2 x}-6=0$
$\Rightarrow x^2+3 \sqrt{2 x}-\sqrt{2 x}-6=0$
$\Rightarrow x(x+3 \sqrt{2})-\sqrt{2}(x-3 \sqrt{2})=0$
$\Rightarrow(x+3 \sqrt{2})(x-\sqrt{2})=0$
$\Rightarrow x+3 \sqrt{2}=0 \text { or } x-\sqrt{2}=0$
$\Rightarrow x=-3 \sqrt{2} \text { or } x=\sqrt{2}$

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