Question
Solve, using formula :$x^2+x-(a+2)(a+1)=0$

Answer

Given quadratic equation is $x^2+x-(a+2)(a+1)=0$
Using quadratic formula,
$\Rightarrow x=\frac{-1 \pm \sqrt{1^2+4(a+2)(a+1)}}{2}$
$ \Rightarrow x=\frac{-1 \pm \sqrt{1+4\left(a^2+3 a+2\right)}}{2} $
$ \Rightarrow x=\frac{-1 \pm \sqrt{4 a^2+12 a+9}}{2} $
$ \Rightarrow x=\frac{-1 \pm \sqrt{2 a+3}^2}{2} $
$ \Rightarrow x=\frac{-1 \pm(2 a+3)}{2} $
$ \Rightarrow x=\frac{-1 \pm(2 a+3)}{2} \text { or } x=\frac{-1 \pm(2 a+3)}{2} $
$ \Rightarrow x=\frac{2 a+2}{2} \text { or } x=\frac{-2 a-4}{2}$
$\Rightarrow x=\frac{2(a+1)}{2} \text { or } x=\frac{2(-a-2)}{2} $
$\Rightarrow x = a +1 \text { or } x =- a -2=-( a +2)$

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