Question
Solve $x^2 + 3x + 9 = 0$

Answer

Here $x^2 + 3x + 9 = 0$
Comparing the given quadratic equation with $ax^2 + bx + c = 0$ we have
a = 1 , b= 3 and c = 9
$\therefore x = \frac{{ - 3 \pm \sqrt {{{(3)}^2} - 4 \times 9} }}{{2 \times 1}}$
$ = \frac{{ - 3 \pm \sqrt { - 27} }}{2} = \frac{{ - 3 \pm 3\sqrt 3 i}}{2}$
Thus $x = \frac{{ - 3 + 3\sqrt 3 i}}{2}$ and $x = \frac{{ - 3 - 3\sqrt 3 i}}{2}$

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