Question
Solve $x^2 + x + 1= 0$

Answer

Here a = 1, b = 1 and c = 1$x = {-b \pm \sqrt{b^2-4ac} \over 2a}$
$b^{2}-4 a c=1^{2}-4 \times 1 \times 1=1-4=-3$
Therefore, the solutions are given by $x=\frac{-1 \pm \sqrt{-3}}{2 \times 1}=\frac{-1 \pm \sqrt{3} i}{2}$

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