Question
Solve $x+\frac{4}{x}=-4 ; x \neq 0$

Answer

$x+\frac{4}{x}=-4$
$\Rightarrow \frac{x^2-4}{x}=-4 $
$ \Rightarrow x^2+4=-4 x $
$\Rightarrow x^2+4 x+4=0 $
$ \Rightarrow(x+2)^2=0 $
$ \Rightarrow(x+2)=0 $
$ \Rightarrow x=-2$

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