Question
Solve
$\frac{x}{2}+5 \leq \frac{x}{3}+6$ where $x$ is a positive odd integer.
$\frac{x}{2}+5 \leq \frac{x}{3}+6$ where $x$ is a positive odd integer.
✓
Answer
$\frac{x}{2}+5 \leq \frac{x}{3}+6 $
$\frac{x}{2}-\frac{x}{3} \leq 6-5$
$\frac{x}{6} \leq 1$
$ x \leq 6$
Since $x$ is a positive odd integer
$\therefore$ Solution set $= {1, 3, 5}$
$\frac{x}{2}-\frac{x}{3} \leq 6-5$
$\frac{x}{6} \leq 1$
$ x \leq 6$
Since $x$ is a positive odd integer
$\therefore$ Solution set $= {1, 3, 5}$
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