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STD 11 - 4.1 complex nubers — Maths STD 11 Science — Question

CBSE BoardEnglish MediumSTD 11 ScienceMathsSTD 11 - 4.1 complex nubers1 Mark
MCQ
Solving $3 - 2yi = {9^x} - 7i$, where ${i^2} = - 1,$ for $x$ and $y$ real, we get
  • ✓
    $x = 0.5\,\,,\,\,y = 3.5$
  • B
    $x = 5\,\,,\,\,y = 3$
  • C
    $x = \frac{1}{2}\,\,,\,\,y = 7$
  • D
    $x = 0,\,y = \frac{{3 + 7i}}{{2i}}$
✓

Answer

Correct option: A.
$x = 0.5\,\,,\,\,y = 3.5$
a
(a) $3 - 2yi = {9^x} - 7i$
Equating real and imaginary parts both sides
${9^x} = 3 \Rightarrow \,{3^{2x}} = {3^1} \Rightarrow 2x = 1 \Rightarrow x = 0.5$
$2y = 7 \Rightarrow \,y = 3.5$.

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