Solving – 8 5x – 3<7, we get: - Vidyadip

MCQ

Solving $ – 8 \leq 5\text{x} – 3<7, $ we get:

A
$\frac{–1}{2}\leq \text{x}\leq 2$
B
$1\leq \text{x}<2$
✓
$ –1\leq\text{x}<2$
D
$ –1<\text{x}\leq2$

✓

Answer

Correct option: C.

$ –1\leq\text{x}<2$

Given,
$-8\leq5\text{x}-3$ and $5\text{x}-3<7$
Let us solve these two inequalities simultaneously.
$-8\leq5\text{x}-3$ and $5\text{x}-3<7$ can be written as:
$– 8\leq5\text{x} –3 < 7$
Adding $3,$ we get
$– 8 + 3\leq5\text{x}-3+3<7+3$
$–5\leq5\text{x}<10$
Dividing by $5,$ we get
$–1\leq\text{x}<2$

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