- ✓

- B$CH_3CH_2NH_2 + HNO_2 \rightarrow CH_3CH_2OH + N_2$
- C$CH_3NH_2 + C_6H_5SO_2Cl \rightarrow CH_3NHSO_2C_6H_5$
- D$(CH_3)_2NH + NaNO_2 + HCl \rightarrow (CH_3)_2N-N=O$



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$(I)\,\,CH_3CH_2OH + HCl \xrightarrow{{Anh.\,\,ZnC{l_2}}}$
$(II)\,\,CH_3CH_2OH + HCl \rightarrow$
$(III)\,\,(CH_3)_3COH + HCl \rightarrow$
$(IV)\,\,(CH_3)_2CHOH + HCl \xrightarrow{{Anh.\,\,ZnC{l_2}}}$

$NO(g) + Br_2 (g) \rightleftharpoons NOBr_2 (g)$
$NOBr_2(g)+ NO(g) \longrightarrow 2NOBr(g)$
If the second step is the rate determining step, the order of the reaction with respect to $NO(g)$ is
$(a)$ $\begin{array}{*{20}{c}}
{C{H_3} - CH - Br} \\
{|\,\,} \\
{\,\,\,\,\,{C_2}{H_5}\,}
\end{array}$ $(b)$ $\begin{array}{*{20}{c}}
{\,\,Br\,} \\
{|\,} \\
{C{H_3} - C - C{H_3}} \\
{|\,} \\
{\,\,\,\,\,{C_2}{H_5}}
\end{array}$ $(c)$ $\begin{array}{*{20}{c}}
{{C_2}{H_5} - CH - C{H_2}Br} \\
{\,\,|\,\,\,\,\,\,\,\,\,\,\,} \\
{{C_2}{H_5}\,\,}
\end{array}$