s p^3 d^2 hybrid orbitals are - Vidyadip

MCQ

$s{p^3}{d^2}$ hybrid orbitals are

A
Linear bipyramidal
B
Pentagonal
C
Trigonal bipyramidal
✓
Octahedral

✓

Answer

Correct option: D.

Octahedral

(d) $s{p^3}{d^2}$ hybrid orbital have octahedral shape

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

NEET STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

The incorrect statement is

Which one of the following is an amino acid

Correct statement about phosphine is /are

$(a)$ It has rotten egg like small

$(b)$ In aquous solution and presence of light it yields white phosphorous and hydrogen

$(c)$ It explodes with $Br_2$

$(d)$ In pure form it is non inflammable

The equivalent weight of an element is $4$. Its chloride has a $V.D$ $59.25$. Then the valency of the element is

Given below are two statements: one is labelled as Assertion(A) and the other is labelled as Reason (R).
Assertion(A) : $E^{\circ}$ value for $Mn ^{3+} / Mn ^{2+}$ couple is much more positive than that of $E ^{\circ}$ value for $Cr ^{3+} / Cr ^{2+}$ or $Fe ^{3+} / Fe ^{2+}$.
Reason ( R ) : Mn have very high value of 3rd ionization energy in comparision to Cr and Fe .
In the light of the above statements, choose the most appropriate answer from the options given below:

The most common oxidation state of an element is $-2.$ The number of electrons present in its outermost shell is

In the $P ^{3-}, S ^{2-}$ and $Cl ^{-}$ions, the increasing order of size is

Addition of $HI$ on the double bond of propene yields isopropyl iodide and not $ n-$ propyl iodide as the major product. This is because the addition proceeds through

$pH$ of blood is maintained constant by mechanism of

The wave number of the first Lyman transition in $H$ atom spectrum is equal to the wave number of second balmer transition in the spectrum of