MCQ
Species having same bond order are:
- A$N _2$
- B$N ^{-} 2$
- C$F ^{+}{ }_2$
- D$O _2^{-}$
✓
Answer
- F+2
- O–2
Explanation:
The total number of electrons in F+2 and O-2 are some, 17 electrons.
$\text{F}^{+}_{2}(17):\text{B}.\text{O}.=\frac{10-7}{2}=1.5$
$\text{O}^{+}_{2}(17):\text{B}.\text{O}.=\frac{10-7}{2}=1.5$
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