MCQ
Splitting a compound using electricity is called:
- AElectrolysis.
- BElectrolyte.
- CElectrokinesis.
- DNone of the above.
Explanation:
Ionic substances can be broken down into the elements they are made from by passing electricity through them. The process is called electrolysis.
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$(I)$ $NO + Br_2 \rightleftharpoons NOBr_2 $ ........ Fast
$(II)$ $NOBr_2 + NO \rightarrow 2NOBr$ ......... Slow
The overall order of this reaction is
| List $-I$ | List $-II$ | ||
|
$(a)$ |
$\begin{array}{*{20}{c}} {O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {R - C - Cl \to R - CHO} \end{array}$ |
$(i)$ |
$Br _{2} / NaOH$ |
| $(b)$ | $\begin{array}{*{20}{c}} {R - C{H_2} - COOH \to R - CH - COOH} \\ {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\ {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Cl} \end{array}$ |
$(ii)$ | $H _{2} / Pd - BaSO _{4}$ |
| $(c)$ | $\begin{array}{*{20}{c}} {O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {R - C - N{H_2} \to R - N{H_2}} \end{array}$ |
$(iii)$ | $Zn ( Hg ) /$ Conc. $HCl$ |
| $(d)$ | $\begin{array}{*{20}{c}} {O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {R - C - C{H_3} \to R - C{H_2} - C{H_3}} \end{array}$ |
$(iv)$ | $Cl _{2}$ / Red $P , H _{2} O$ |
Choose the correct answer from the options given below: