MCQ
$\sqrt {(3 + \sqrt 5 )} $ is equal to
- A$\sqrt 5 + 1$
- B$\sqrt 3 + \sqrt 2 $
- ✓$(\sqrt 5 + 1)/\sqrt 2 $
- D${1 \over 2}(\sqrt 5 + 1)$
$3 + \sqrt 5 = \,x + y + 2\sqrt {xy} $. Obviously $x + y = 3$
and $4xy = 5$. So ${(x - y)^2} = 9 - 5 = 4$ or $(x - y) = 2$
After solving $x = {5 \over 2},y = {1 \over 2}$.
Hence, $\sqrt {3 + \sqrt 5 } = \sqrt {{5 \over 2}} + \sqrt {{1 \over 2}} = {{\sqrt 5 + 1} \over {\sqrt 2 }}$.
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