MCQ
$\sqrt{-8-6 i}=$
  • A
    $1 \pm 3 i$
  • $\pm(1-3 i)$
  • C
    $\pm(1+3 i)$
  • D
    $\pm(3- i )$

Answer

Correct option: B.
$\pm(1-3 i)$
(B)
Let $\sqrt{-8-6 i }=x+ i y$
$\Rightarrow-8-6 i =(x+ i y)^2$
$\Rightarrow x^2-y^2=-8$ and $2 x y=-6$
By solving, we get
$x=1, y=-3$ and $x=-1, y=3$
$\therefore x+ i y= \pm(1-3 i )$
Alternate method:
Here, $b <0$
Square root of $z = a + ib$ is
$\begin{aligned} \sqrt{ a + ib } & = \pm\left[\sqrt{\frac{| z |+ a }{2}}+ i \sqrt{\frac{| z |- a }{2}}\right], \text { for } b >0 \\ & = \pm\left[\sqrt{\frac{| z |+ a }{2}}- i \sqrt{\frac{| z |- a }{2}}\right], \text { for } b <0\end{aligned}$
$\therefore \sqrt{-8-6 i }= \pm\left[\sqrt{\frac{10-8}{2}}- i \sqrt{\frac{10+8}{2}}\right]= \pm(1-3 i )$

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