MCQ
$\sqrt{\frac{1+\sin\theta}{1-\sin\theta}}$ is equal to :
  • $\sec\theta+\tan\theta$
  • B
    $\sec\theta-\tan\theta$
  • C
    $\sec^2\theta+\tan^2\theta$
  • D
    $\sec^2\theta-\tan^2\theta$

Answer

Correct option: A.
$\sec\theta+\tan\theta$
$\sqrt{\frac{1+\sin\theta}{1-\sin\theta}}=\sqrt{\frac{(1+\sin\theta)(1+\sin\theta)}{(1-\sin\theta)(1+\sin\theta)}}$
$=\sqrt{\frac{(1+\sin\theta)^2}{1-\sin^2\theta}}$
$=\sqrt{\frac{(1+\sin\theta)^2}{\cos^2\theta}}$
$=\frac{1+\sin\theta}{\cos\theta}=\frac{1}{\cos\theta}+\frac{\sin\theta}{\cos\theta}$
$=\sec\theta+\tan\theta$

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