MCQ
$\sqrt{3} x^2+11 x+6 \sqrt{3}=$
- A$(\sqrt{3} x+2)(x-3 \sqrt{3})$
- ✓$(\sqrt{3} x+2)(x+3 \sqrt{3})$
- C$(\sqrt{3} x-2)(x-3 \sqrt{3})$
- D$(x-2)(x+3 \sqrt{3})$
✓
Answer
Correct option: B.
$(\sqrt{3} x+2)(x+3 \sqrt{3})$
B
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The solution of the simultaneous equations $3 x \quad 2 y=5$ and $x+2 y=1$ is :
→What is the pure surd for $5 \sqrt[3]{2}$ ?
→In a $\triangle ABC , AB = AC$ and $\angle B =50^{\circ}$. Then $\angle A =$
→0.3 when expressed as a ratio of two integers, becomes :
If the lengths of two diagonals of a rhombus are 6 cm and 4 cm , then its area is :
The height of 8 students in a class are 102 cm, 107 cm, 82 cm, 103 cm, 97 cm, 111 cm, 88 cm and 94 cm. The mean height is:
If $\left(x+\frac{1}{x}\right)^2=3$, then $x^3+\frac{1}{x^3}=$
→Four rational numbers $p, q, r$ and $s$ are such that $q$ is the reciprocal of $p$ and $s$ is the reciprocal of $r$. The value of the expression
$\left\{\left(p+\frac{1}{q}\right) \div\left(r+\frac{1}{s}\right)\right\} \quad\left\{\left(s+\frac{1}{r}\right) \quad\left(q+\frac{1}{p}\right)\right\}$ is equal to:
→$\left\{\left(p+\frac{1}{q}\right) \div\left(r+\frac{1}{s}\right)\right\} \quad\left\{\left(s+\frac{1}{r}\right) \quad\left(q+\frac{1}{p}\right)\right\}$ is equal to:
If $\angle ADB$ of the rhombus ABCD is 30 , then $\angle ACB =$
→