Question
$\sqrt[3]{...}={\sqrt[3]{4}}\times{\sqrt[3]{5}}\times\sqrt[3]{6}$

Answer

$\sqrt[3]{\underline{4\times5\times6}}=120$
Solution:
$\because\sqrt[3]{4\times5\times6}={\sqrt[3]{4}}\times{\sqrt[3]{5}}\times\sqrt[3]{6}$

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