MCQ
$\sqrt[4]{\sqrt[3]{2^2}}$ equals
- A$2^{-1 / 6}$
- B$2^{-6}$
- ✓$2^{1 / 6}$
- D$2^6$
✓
Answer
Correct option: C.
$2^{1 / 6}$
(c)
$\sqrt[4]{\sqrt[3]{2^2}}=\sqrt[4]{\left(2^2\right)^{1 / 3}}=\left(2^{2 / 3}\right)^{1 / 4}=2^{\frac{2}{3} \cdot \frac{1}{4}}=2^{1 / 6}$
$\sqrt[4]{\sqrt[3]{2^2}}=\sqrt[4]{\left(2^2\right)^{1 / 3}}=\left(2^{2 / 3}\right)^{1 / 4}=2^{\frac{2}{3} \cdot \frac{1}{4}}=2^{1 / 6}$
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