Question
$\sqrt[4]{\sqrt[3]{2^2}}$ is equal to:
✓
Answer
- $2^{\frac{1}{6}}$
Solution:
$\sqrt[4]{\sqrt[3]{2^2}}=\sqrt[4]{(2)^{\frac{2}{3}}}$
$=(2)^{\frac{2}{3}\times\frac{1}{4}}$
$=(2)^{\frac{1}{6}}$
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