MCQ
Square of $\big(\frac{-2}{3}\big)$ is:
  • A
    $\frac{-2}{3}$
  • B
    $\frac{2}{3}$
  • C
    $\frac{-4}{9}$
  • $\frac{4}{9}$

Answer

Correct option: D.
$\frac{4}{9}$
Square of $\frac{-2}{3}\text{ is }\big(\frac{-2}{3}\big)^{2}$
So, $\big(\frac{-2}{3}^{2}\big)=\big(\frac{-2}{3}\big)\times\big(\frac{-2}{3}\big)$
$=\frac{4}{9}$
[$\because$ multiplication of two rational number with same sign is always positive]

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