Standard deviations for first 10 natural numbers is: 1. 5.5 2. 3.… - Vidyadip

Question

Standard deviations for first 10 natural numbers is:

5.5
3.87
2.97
2.87

✓

Answer

2.87

Solution:

We know that SD of first n natural numbers $\sqrt{\frac{\text{n}^2-1}{12}}$

Here, $\text{n}=10$

$\therefore\ \text{SD}=\sqrt{\frac{(10)^2-1}{12}}=\sqrt{\frac{99}{12}} $

$=\sqrt{8.25}=2.87$

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