MCQ
Standard deviations for first $10$ natural numbers is:
  • A
    $5.5$
  • B
    $3.87$
  • C
    $2.97$
  • $2.87$

Answer

Correct option: D.
$2.87$
We know that $SD$ of first $n$ natural numbers $\sqrt{\frac{\text{n}^2-1}{12}}$
Here, $\text{n}=10$
$\therefore\ \text{SD}=\sqrt{\frac{(10)^2-1}{12}}$
$=\sqrt{\frac{99}{12}} $
$=\sqrt{8.25}$
$=2.87$

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