MCQ
Standard Gibbs energy change $\Delta_{ r } G ^0$ is related to the equilibrium constant of the reaction as follows:
  • A
    $\Delta_{ r } G ^0=- R \ln K$
  • B
    $\Delta_{ r } G ^0=- nRT \ln K$
  • $\Delta_{ r } G ^0=- RT \ln K$
  • D
    $\Delta_{ r } G ^0=- T \ln K$

Answer

Correct option: C.
$\Delta_{ r } G ^0=- RT \ln K$
(c) $\Delta_{ r } G ^0=- RT \ln K$
Explanation: $\Delta_{ r } G ^0=- RT \ln K$ where $\Delta_{ r } G ^0$ is standard Gibbs energy change, K is the equilibrium constant, $R$ is the universal gas constant and $T$ is the temperature in kelvin scale.

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