MCQ
Standing waves are produced in a $10 \;m$ long stretched string. If the string vibrates in $5$ segments and the wave velocity is $20\; m/s$, the frequency is ... $Hz$
- A$2$
- B$4$
- ✓$5$
- D$10$
✓
Answer
Correct option: C.
$5$
c
(c) String vibrates in five segment so $\frac{5}{2}\lambda = l$
(c) String vibrates in five segment so $\frac{5}{2}\lambda = l$
==> $\lambda = \frac{{2l}}{5}$
Hence $n = \frac{v}{\lambda } = 5 \times \frac{v}{{2l}}$$ = 5 \times \frac{{20}}{{2 \times 10}} = 5$$Hz$
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