Question
State modern periodic law.
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$\text{Al(OH)}_3\xrightarrow{\ \ \ \ \ \ \ \ \ \ \ }\text{Al}_2\text{O}_3\ +\ \text{H}_2\text{O}$
$\text{CH}_4\ +\ \text{O}_2\xrightarrow{\ \ \ \ \ \ \ \ \ \ \ \ }\text{CO}_2\ +\ \text{H}_2\text{O}$