How does Raoult’s law become a special case of Henry’s law?
The partial pressure of the volatile component or gas is directly proportional to its mole fraction in solution. Only the proportionality constant KH differs from PoA. Thus, Raoult’s law becomes a special case of Henry’s law in which KH becomes equal to PoA.
| WA = 50g; | Kf = 5∙12K kg/ mol- 1; | ΔTf = 0∙40K |
$\Delta\text{T}_{f}=\text{K}_{f}\frac{\text{W}_{B}\times{1000}}{\text{M}_{B}\times\text{W}_{A}\text{(in grams)}}$
$\text{M}_{B}=\text{K}_{f}\frac{\text{W}_{B}\times{1000}}{\Delta\text{T}_{f}\times\text{W}_{A}}$
$\text{M}_{B}=\frac{\text{5.12}\times{1}\times{1000}}{\text{0.40}\times\text{50}}$
= 256g mol-1
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| | Column I (Complex ion) | | Column II (Colour) |
| a. | [Co(NH3)6]3+ | 1. | Violet |
| b. | [Ti(H2O)6]3+ | 2. | Green |
| c. | [Ni(H2O)6]2+ | 3. | Pale blue |
| d. | [Ni(H2O)4(en)]2+ (aq) | 4. | Yellowish orange |
| | | 5. | Blue |