Question
State the expression for the capacitance of a parallel-plate capacitor filled with a dielectric. Explain how its capacitance can be increased.

Answer

The capacitance of a parallel-plate capacitor filled with a dielectric is $C =\frac{A k \varepsilon_0}{d}$
where $A$ is the area of each plate, $k$ is the relative permittivity (dielectric constant) of the medium between the plates, $\varepsilon_0$ is the permittivity of free space and $d$ is the uniform plate separation.
The capacitance of a parallel-plate capacitor can be increased by
1. increasing the area of each plate
2. decreasing the distance between the two plates
3. filling the space between the two plates by a medium of greater relative permittivity.

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