Maharashtra BoardEnglish MediumSTD 12 SciencePhysicsQuestion Bank [ 2022 ]3 Marks
Question
State the laws of vibrating strings
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Answer
The fundamental frequency of a vibrating string under tension is given as, $n =\frac{1}{2 l} \sqrt{\frac{ T }{ m }}$
From this formula, three laws of vibrating string can be given as follows:
i. Law of length: The fundamental frequency of vibrations of a string is inversely proportional to the length of the vibrating string if tension and mass per unit length are constant.
$\therefore n \alpha \frac{1}{l}$ .(if $T$ and $m$ are constant.)
ii. Law of tension: The fundamental frequency of vibrations of a string is directly proportional to the square root of tension if the vibrating length and mass per unit length are constant.
$\therefore n \alpha \sqrt{ T }$
(if I and $m$ are constant.)
iii. Law of linear density: The fundamental frequency of vibrations of a string is inversely proportional to the square root of mass per unit length (linear density), if the tension and vibrating length of the string are constant.
$\therefore n \alpha \frac{1}{\sqrt{ m }}$ (if $T$ and I are constant.)
If $r$ is the radius and $r$ is the density of the material of string, linear density is given as
Linear density $=$ mass per unit length
$=$ volume per unit length $\times$ density
$ =\frac{\pi r^2 l}{l} \times \rho$
$=\pi r^2 \rho$
As $n \propto \frac{1}{\sqrt{ m }}$, if $T$ and I are constant, we have,
$n \propto \frac{1}{\sqrt{\pi r^2 \rho}}$
i.e., $n \propto \frac{1}{\sqrt{\rho}}$ and $n \propto \frac{1}{ r }$
Thus the fundamental frequency of vibrations of a stretched string is inversely proportional to the radius of string and the square root of the density of the material of vibrating string.
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