Question
State whether the following number is rational or irrational:$(3+\sqrt{3})^2$
✓
Answer
$(3+\sqrt{3})^2$
$=(3)^2+(\sqrt{3})^2+2 \times 3 \times \sqrt{3}$
$=9+3+6 \sqrt{3}$
$=12+6 \sqrt{3},$
which is irrational .
$=(3)^2+(\sqrt{3})^2+2 \times 3 \times \sqrt{3}$
$=9+3+6 \sqrt{3}$
$=12+6 \sqrt{3},$
which is irrational .
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