STATEMENT-1: [Fe (H_2 O )_5 NO ] SO_4 is paramagnetic. and STATEM… - Vidyadip

MCQ

$STATEMENT-1$: $\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_5 \mathrm{NO}\right] \mathrm{SO}_4$ is paramagnetic. and

$STATEMENT-2$: The $\mathrm{Fe}$ in $\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_5 \mathrm{NO}_3 \mathrm{SO}_4\right.$ has three unpaired electrons.

✓
STATEMENT-$1$ is True, STATEMENT-$2$ is True; STATEMENT-$2$ is correct explanation for STATEMENT-$1$
B
STATEMENT-$1$ is True, STATEMENT-$2$ is True; STATEMENT-$2$ is $NOT$ a correct explanation for STATEMENT-$1$
C
STATEMENT-$1$ is True, STATEMENT-$2$ is False
D
STATEMENT-$1$ is False, STATEMENT-$2$ is True

✓

Answer

Correct option: A.

STATEMENT-$1$ is True, STATEMENT-$2$ is True; STATEMENT-$2$ is correct explanation for STATEMENT-$1$

a
$\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_5 \mathrm{NO}\right] \mathrm{SO}_4$

Here $\mathrm{Fe}$ has $+1$ oxidation state.

$\mathrm{Fe}^{+}=3 \mathrm{~d}^6 4 \mathrm{~s}^1$ in presence of $\mathrm{NO}^{+} 4 \mathrm{~s}^1$ electron are paired in $3 \mathrm{~d}$ sub shell.

So electronic configuration of $\mathrm{Fe}^{+}$is

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$(i)\,\,\begin{matrix}
CHO\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
{{(CH-OH)}_{3}}\,\,\,\,\,\, \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
\,\,C{{H}_{2}}-OH\,\,\,\,\,\,\,\,\,\, \\
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C{{H}_{2}}OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
{{(CH-OH)}_{4}}\,\,\,\,\,\, \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
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