Statement (A): The matrices A= [ rr 2 & 5 7 & -4 ] and B= [ rr 2 … - Vidyadip

MCQ

Statement (A): The matrices $A=\left[\begin{array}{rr}2 & 5 \\ 7 & -4\end{array}\right]$ and $B=\left[\begin{array}{rr}2 & 5 \\ 7 & -4\end{array}\right]$ are equal.
Statement (B): The Matrices $A=\left[\begin{array}{rrr}2 & 3 & 0 \\ 7 & -6 & 5\end{array}\right]$ and $B=\left[\begin{array}{rrr}2 & 0 & 3 \\ 7 & -6 & 5\end{array}\right]$ are equal.
Which of the statement is valid?

✓
Only A
B
Only B
C
Both A and B
D
Neither A nor B

✓

Answer

Correct option: A.

Only A

(a) Only A
Explanation
For statement A,
The matrices $A=\left[\begin{array}{rr}2 & 5 \\ 7 & -4\end{array}\right]$ and $B=\left[\begin{array}{rr}2 & 5 \\ 7 & -4\end{array}\right]$ are equal, because both are of the same order 2 $\times 2$ and their corresponding entries are equal.
Hence, Statement A is correct
For statement B,
The matrice $A=\left[\begin{array}{rrr}2 & 3 & 0 \\ 7 & -6 & 5\end{array}\right]$ and $B=\left[\begin{array}{rrr}2 & 0 & 3 \\ 7 & -6 & 5\end{array}\right]$ are not equal, because (1, 2)th entry of $A \neq$ $(1,2)$ th entry of $B$, even though both matrices $A$ and $B$ one of the same order $2 \times 3$.
Hence, statement B is incorrect.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "MCQ" from Matrices→Matrices — all question types→Mathematics STD 10 question papers→ICSE Board STD 10 question papers→ICSE Board question paper generator→

Similar questions

Which term of the AP $4,9,14,19, \ldots$ is $124 ?$

By purchasing 25 gas shares from 40 each a man gets 4% profit on his investment. The rate percentage is the company paying will be:

The transformation is an ___________ , if $k=1$ where $k$ is the scale factor of a given size transformation.

If the common difference of an A.P. is 5 , then the difference in its $30^{\text {th }}$ and $15^{\text {th }}$ terms is:

The numbers $a, b, c$ are in G.P. if

For a grouped frequency distribution, we use $\overline{\mathrm{X}}=\mathrm{A}+\frac{\sum f d}{\Sigma f}$ to find the mean using shortcut method: Here $d$ stands for:

The point which lies on the perpendicular bisector of the line segment joining the points $A (-2,-5)$ and $B (2,5)$ is:

In a grouped frequency distribution, the class with maximum frequency is called:

In the given figure, if $O$ is the centre of the circle and $\angle A O C=130^{\circ}$, then $\angle \mathrm{ABC}$ is equal to :

If $-x \geq-3$ then :