MCQ
Strong reducing behaviour of $H _{3} PO _{2}$ is due to
- ALow oxidation state of $P$
- BPresence of one $-OH$ group and two $P-H$ bonds
- CPresence of two $-OH$ groups and one $P-H$ bonds
- ✓Low coordination number of $P$
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Statement $(I)$ : Oxygen being the first member of group $16$ exhibits only $-2$ oxidation state.
Statement $(II)$ : Down the group $16$ stability of $+4$ oxidation state decreases and $+6$ oxidation state increases.
In the light of the above statements, choose the most appropriate answer from the options given below: