MCQ
Strong reducing behaviour of $H_3PO_2$ is due to
- AHigh oxidation state of phosphorus
- BPresence of two $-OH$ groups and one $P-H$ bond
- ✓Presence of one $-OH$ group and two $P-H$ bonds
- DHigh electron gain enthalpy of phosphorus
All oxy-acid of phosphorus which contain $\mathrm{P}-\mathrm{H}$ bond act as reductant.
presence of one - $\mathrm{OH}$ group and two $\mathrm{P}-\mathrm{H}$ bonds
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|
सूची-$I$ coordination compounds |
सूची-$II$ numbar of unpaired electrons |
| $A$ $\left[ Cr ( CN )_6\right]^{3-}$ | $I$ $0$ |
| $B$ $\left[ Fe \left( H _2 O \right)_6\right]^{2+}$ | $II$ $3$ |
| $C$ $\left[ Co \left( NH _3\right)_6\right]^{3+}$ | $III$ $2$ |
| $D$ $\left[ Ni \left( NH _3\right)_6\right]^{2+}$ | $IV$ $4$ |
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