MCQ
Strong reducing behaviour of $\mathrm{H}_3 \mathrm{PO}_2$ is due to
  • A
    Low oxidation state of phosphorus.
  • B
    Presence of two$-OH$ groups and one $P-H$ bond.
  • Presence of one$-OH$ group and two $P-H$ bonds.
  • D
    High electron gain enthalpy of phosphorus.

Answer

Correct option: C.
Presence of one$-OH$ group and two $P-H$ bonds.
In $\mathrm{H}_3 \mathrm{PO}_2,$ two H atoms are bonded directly to $P$ atom which imparts reducing character to the acid.

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