- A$\begin{array}{l}CHCl\\{\rm{||}}\\CHAsC{l_3}\end{array}$
- B$\begin{array}{l}CHC{l_2}\\{\rm{|}}\\CHAsC{l_3}\end{array}$
- ✓$\begin{array}{l}CHCl\\||\\CHAsC{l_2}\end{array}$
- DNone of these
$\begin{array}{*{20}{c}}
{CH} \\
{|||\,\,\,\,} \\
{CH}
\end{array} + \mathop {\begin{array}{*{20}{c}}
{Cl\,\,\,\,} \\
{|\,\,\,\,\,\,\,} \\
{AsC{l_2}}
\end{array}}\limits_{{\text{Arsenic}}{\mkern 1mu} {\mkern 1mu} {\text{trichloride}}} \xrightarrow{{Anhydrous\,AlC{l_3}}}\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,CHCl\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{CH\,\,AsC{l_2}}
\end{array}}\limits_{{\text{Lewisite }}\left( {\beta {\text{ - Chlorovinyl }}{\mkern 1mu} {\mkern 1mu} {\text{dichloroarsine}}} \right)} $
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Precipitate $X$ is
$(A)$ $Fe _4\left[ Fe ( CN )_6\right]_3$
$(B)$ $Fe \left[ Fe ( CN )_6\right]$
$(C)$ $K _2 Fe \left[ Fe ( CN )_6\right]$
$(D)$ $KFe \left[ Fe ( CN )_6\right]$
Among the following, the brown ring is due to the formation of
$(A)$ $\left[ Fe ( NO )_2\left( SO _4\right)_2\right]^{2-}$
$(B)$ $\left[ Fe ( NO )_2\left( H _2 O \right)_4\right]^{3+}$
$(C)$ $\left[ Fe ( NO )_4\left( SO _4\right)_2\right]$
$(D)$ $\left[ Fe ( NO )\left( H _2 O \right)_5\right]^{2+}$
$X-Y-Z$
