Study the velocity-time graph and calculate. 1. The acceleration from A to B. 2. The acceleration from B to C. 3. The distance covered in the region ABE. 4. The average velocity from C to D. 5. The distance covered in the region BCFE.

1. a=(25-0) (3-0) =8.3m/s^ 2 2. a=(20-25) (4-3) =5m/s^ 2 3. Distance = Area of triangle ABE. 4. =1 2 3 25=37.5m 5. V=(20-0) 2 =10m/s This Distance = Area of trapezium BCFE. =1 2 (25+20) (4-3)=22.5m

Study the velocity-time graph and calculate. 1. The acceleration …

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Question

Study the velocity-time graph and calculate.

The acceleration from $A$ to $B.$
The acceleration from $B$ to $C.$
The distance covered in the region $ABE.$
The average velocity from $C$ to $D.$
The distance covered in the region $BCFE.$

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Answer

$\text{a}=\frac{(25-0)}{(3-0)}=8.3\text{m/s}^{2}$
$\text{a}=\frac{(20-25)}{(4-3)}=5\text{m/s}^{2}$
Distance $=$ Area of triangle $ABE.$
$=\frac{1}{2}\times3\times25=37.5\text{m}$
$\text{V}=\frac{(20-0)}{2}=10\text{m/s}$

This Distance $=$ Area of trapezium $BCFE.$
$=\frac{1}{2}(25+20)\times(4-3)=22.5\text{m}$

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