Question
Study the velocity-time graph and calculate.


  1. The acceleration from A to B.
  2. The acceleration from B to C.
  3. The distance covered in the region ABE.
  4. The average velocity from C to D.
  5. The distance covered in the region BCFE.

Answer

  1. $\text{a}=\frac{(25-0)}{(3-0)}=8.3\text{m/s}^{2}$

  2. $\text{a}=\frac{(20-25)}{(4-3)}=5\text{m/s}^{2}$

  3. Distance = Area of triangle ABE.

  4. $=\frac{1}{2}\times3\times25=37.5\text{m}$

  5. $\text{V}=\frac{(20-0)}{2}=10\text{m/s}$

This Distance = Area of trapezium BCFE.

$=\frac{1}{2}(25+20)\times(4-3)=22.5\text{m}$

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