Gujarat BoardEnglish MediumSTD 6MATHSFractions and Decimals3 Marks
Question
Subtract $\frac{1}{6}$ from $\frac12.$
✓
Answer
Converting the given fractions into lke fractions.$LCM$ of the denominators of $\frac16$ and $\frac12$
$\begin{array}{c|c}2&6,2\\\hline3&3,1\\\hline&1,1\end{array}$
$\therefore$ $LCM$ of $6$ and $2 = 2 \times 3 = 6$
Now, we convert the given fractions into equivalent fractions with denominator $6$.
So, $\frac{1\times1}{6\times1}=\frac16$ and $\frac{1}{2}=\frac{1\times3}{2\times3}=\frac{3}{6}$
$\therefore\frac12-\frac16=\frac{3}{6}-\frac{1}{6}=\frac{3-1}{6}=\frac{3\div2}{6\div2}=\frac13$
[$\because$ for reducing a fraction to its lowest term, we divide its numerator and denominator by their $HCF$]
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