Question
Subtract: $-3p2 + 3pq + 3px$ from $3p(-p - a - r)$

Answer

The required difference is
$ 3 p(-p-a-r)-\left(-3 p^2+3 p q+3 p x\right) $
$ =-3 p^2-3 a p-3 p r+3 p^2-3 p q-3 p x $
$ =\left(-3 p^2+3 p^2\right)-3 a p-3 p r-3 p q-3 p x $

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