Question
Subtract: $3pq(p – q)$ from $2pq(p + q).$
✓
Answer
We have $3pq(p – q) = 3p^2q – 3pq^2....(i)$
$2pq(p + q) = 2p^2q + 2pq^2......(ii)$
Subtracting eq$(i)$ from eq$(ii)$,
Thus, the difference is $-p^2q + 5pq^2$
$2pq(p + q) = 2p^2q + 2pq^2......(ii)$
Subtracting eq$(i)$ from eq$(ii)$,
Thus, the difference is $-p^2q + 5pq^2$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Find the value of $x,$ if:
$5 x=(50)^2-(40)^2$
→$5 x=(50)^2-(40)^2$
Find the smallest number by which $135$ must be divided to obtain a perfect cube.
→Find the cube root of the following rational numbers: $\frac{686}{-3456}$
→In how much time would Rs. $5000$ amount to Rs. $6655$ at $10\%$ per annum compound interest?
→In the given figure, ABCD and BDCE are parallelograms with common base $D C$. If $B C \perp B D$, then find $\angle B E C$.
→A king wanted to reward his advisor, a wise man of the kingdom. So he asked the wiseman to name his own reward. The wiseman thanked the king but said that he would ask only for some gold coins each day for a month. The coins were to be counted out in a pattern of one coin for the first day, $3$ coins for the second day, $5$ coins for the third day and so on for $30$ days. Without making calculations, find how many coins will the advisor get in that month?
→If x $=\Big(\frac{4}{5}\Big)^{-2}\div\Big (\frac{1}{4}\Big)^{2},$ find the value of $\text{x}^{1}$
→Which of the following numbers are cubes of negative integers. $−2197$
→Rearrange suitably and find the sum in each of the following
(i) $\frac{2}{3}+\frac{9}{2}+\frac{7}{4}+\left(\frac{-6}{3}\right)+\frac{-3}{2}$
(ii) $\frac{-5}{7}+\frac{5}{6}+\frac{1}{7}+3+\left(\frac{-13}{6}\right)$
→(i) $\frac{2}{3}+\frac{9}{2}+\frac{7}{4}+\left(\frac{-6}{3}\right)+\frac{-3}{2}$
(ii) $\frac{-5}{7}+\frac{5}{6}+\frac{1}{7}+3+\left(\frac{-13}{6}\right)$
Tathagat has written several numbers that leave a remainder of 2 when divided by $6 . He$ claims, "If you add any three such numbers, the sum will always be a multiple of $6 . "$ Is Tathagat's claim true?
→