Question
Subtract:
$6 x^3-7 x^2+5 x-3$ from $4-5 x+6 x^2-8 x^3$
$6 x^3-7 x^2+5 x-3$ from $4-5 x+6 x^2-8 x^3$
✓
Answer
Required expression:
$=\left(4-5 x+6 x^2-8 x^3\right)-\left(6 x^3-7 x^2+5 x-3\right)$
$=4-5 x+6 x^2-8 x^3-6 x^3+7 x^2-5 x+3$
$=-8 x^3-6 x^3+7 x^2+6 x^2-5 x-5 x+3+4$
$=-14 x^3+13 x^2-10 x+7$
$=\left(4-5 x+6 x^2-8 x^3\right)-\left(6 x^3-7 x^2+5 x-3\right)$
$=4-5 x+6 x^2-8 x^3-6 x^3+7 x^2-5 x+3$
$=-8 x^3-6 x^3+7 x^2+6 x^2-5 x-5 x+3+4$
$=-14 x^3+13 x^2-10 x+7$
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