Question
Subtract: $7p(3q + 7p)$ from $8p(2p - 7q)$
✓
Answer
The required difference is given by
$8p(2p - 7q) - 7p(3q + 7p)$
$ =16 p^2-56 p q-21 p q-49 p^2 $
$ =\left(16 p 2-49 p^2\right)+(-56 p q-21 p q) $
$ =-33 p^2-77 p q $
$8p(2p - 7q) - 7p(3q + 7p)$
$ =16 p^2-56 p q-21 p q-49 p^2 $
$ =\left(16 p 2-49 p^2\right)+(-56 p q-21 p q) $
$ =-33 p^2-77 p q $
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