Question
Subtract:
$\frac{-8}{9}\text{ from }\frac{-3}{5}$
$\frac{-8}{9}\text{ from }\frac{-3}{5}$
✓
Answer
$\frac{-8}{9}\text{ from }\frac{-3}{5}$Lcm of 9 and 5 = 45
$\therefore\frac{-8}{9}=\frac{-8\times5}{9\times5}=\frac{-40}{45}$
$\frac{-3}{5}=\frac{-3\times9}{5\times9}=\frac{-27}{45}$
$\therefore\frac{-3}{5}-\Big(\frac{-8}{9}\Big)=\frac{-3}{5}+\frac{8}{9}$
$=\frac{27}{45}+\frac{-27+40}{45}=\frac{13}{45}$
$\therefore\frac{-8}{9}=\frac{-8\times5}{9\times5}=\frac{-40}{45}$
$\frac{-3}{5}=\frac{-3\times9}{5\times9}=\frac{-27}{45}$
$\therefore\frac{-3}{5}-\Big(\frac{-8}{9}\Big)=\frac{-3}{5}+\frac{8}{9}$
$=\frac{27}{45}+\frac{-27+40}{45}=\frac{13}{45}$
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