Question
Subtract as indicated:$\frac{8}{3}-\frac{5}{9}$
✓
Answer
$\frac{8}{3}-\frac{5}{9}$
$=\frac{8\times3}{3\times3}-\frac{5\times1}{9\times1}$
$=\frac{24}{9}-\frac{5}{9}$ (because $LCM$ of $3$ and $9$ is $9$)
$=\frac{24-5}{9}$
$=\frac{19}{9}$
$=\frac{8\times3}{3\times3}-\frac{5\times1}{9\times1}$
$=\frac{24}{9}-\frac{5}{9}$ (because $LCM$ of $3$ and $9$ is $9$)
$=\frac{24-5}{9}$
$=\frac{19}{9}$
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