Question
Subtract the first rational number from the second in the following:
$\frac{-7}{9},\frac{4}{9}$
$\frac{-7}{9},\frac{4}{9}$
✓
Answer
$\frac{-7}{9},\frac{4}{9}$
$\frac{-7}{9}$ from $\frac{4}{9}=\frac{4}{9}-\Big(\frac{-7}{9}\Big)$
$=\frac{4}{9}+\frac{7}{9}=\frac{4+7}{9}$
$=\frac{11}{9}$
$\frac{-7}{9}$ from $\frac{4}{9}=\frac{4}{9}-\Big(\frac{-7}{9}\Big)$
$=\frac{4}{9}+\frac{7}{9}=\frac{4+7}{9}$
$=\frac{11}{9}$
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